
1 Report for Julia Witkowsky
Find the right Julia Witkowsky by their age, location, and contact info below
Julia H Witkowsky
, Age 101AKA:
Julia Witkowski •
Julie Witkowsky •
Julia Wikowsky
Lives in:
135 Great East Neck Rd, West Babylon, NY
Phone number(s):
(631) 957-8954 •
(631) 321-1614 •
(631) 587-0239 •
(516) 957-8954
- Phone Numbers (4)
- Addresses (3)
- Email Addresses (0)
- Social Profiles (0)
- Relatives (3)
Julia Witkowsky Summary
1 individuals identified as Julia Witkowsky were located throughout the United States across all 50 states. Predominantly, they reside in Buffalo, NY, with subsequent concentrations in Lindenhurst, NY and West Babylon, NY. Public records indicate that the ages of these individuals span from 101 to 101 years old. Additionally, our search revealed a collective total of 4 phone numbers associated with Julia Witkowsky, one of which is (631) 321-1614. 631, 516 are some of the most popular area codes for these people.Julia Witkowsky in Numbers
Statistics based on the US Census data for all 1 people with this name.We are always updating our data. Please check back later for results.
Alive vs. Deceased
- Deceased17%
- Alive83%
We are always updating our data. Please check back later for results.
- Gmail
- Yahoo
- Outlook
- AOL
- Other
- 63%
- 11%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
We are always updating our data. Please check back later for results.
Julia Witkowsky F.A.Q.
Discover our primary finding for Julia Witkowsky in under 60 seconds!
How old is Julia Witkowsky?
Julia Witkowsky is 101 years old.
What is Julia Witkowsky's last known address?
135 Great East Neck Rd, West Babylon, NY, 11704
What is Julia Witkowsky's last contact number?
Julia Witkowsky's phone number is (631) 321-1614.
What is Julia Witkowsky's email address?
j*****@hotmail.com
Is Julia Witkowsky married?
No marriage records found matching the name Julia Witkowsky.
Does Julia Witkowsky have a criminal record?
No criminal records found matching the name Julia Witkowsky.