
1 Report for D Vanatta
Find the right D Vanatta by their age, location, and contact info below
D Scott Vanatta
, Age 81AKA:
David Scott Vanatta •
Scott Scott Vanatta •
Scott D Vanatta
Lives in:
385 Patton Rd, Brackney, PA
Phone number(s):
(607) 797-2568
- Phone Numbers (1)
- Addresses (5)
- Email Addresses (0)
- Social Profiles (0)
- Relatives (4)
D Vanatta Summary
1 individuals identified as D Vanatta were located throughout the United States across all 50 states. Predominantly, they reside in Florida, with subsequent concentrations in New York and Pennsylvania. Public records indicate that the ages of these individuals span from 81 to 81 years old. Some possible relatives include Ingeborg Vanatta and Margaret Butler. Additionally, our search revealed a collective total of 4 phone numbers associated with D Vanatta, one of which is (813) 349-5423. 813, 570, 607 are some of the most popular area codes for these people.D Vanatta in Numbers
Statistics based on the US Census data for all 1 people with this name.Single vs. Married
- Single45%
- Married55%
Alive vs. Deceased
- Deceased17%
- Alive83%
- <25k
- 25-50k
- 50-75k
- 75-100k
- 100-125k
- 125-150k
- 150-200k
- 200k+
- 17.2%
- 20%
- 17.8%
- 13.5%
- 10%
- 8%
- 10.3%
- 13.1%
The average income for D Vanatta is 68k
- Gmail
- Yahoo
- Outlook
- AOL
- Other
- 63%
- 11%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
62
Average Age
- 0-1823%
- 18-259%
- 25-3514%
- 35-4513%
- 45-5512%
- 55-6513%
- 65-8515%
- 85+2%
D Vanatta F.A.Q.
Discover our primary finding for D Vanatta in under 60 seconds!
How old is D Vanatta?
D Vanatta is 81 years old.
What is D Vanatta's last known address?
385 Patton Rd, Brackney, PA, 18812
What is D Vanatta's last contact number?
D Vanatta's phone number is (813) 349-5423.
What is D Vanatta's email address?
No email address found.
Is D Vanatta married?
54.76% of people matching the name D Vanatta are married.
Does D Vanatta have a criminal record?
No criminal records found matching the name D Vanatta.