
1 Report for Jacob Stackhouse
Find the right Jacob Stackhouse by their age, location, and contact info below
Jacob H Stackhouse
, Age 90Lives in:
2315 Knobhill Rd, York, PA
Phone number(s):
(717) 854-4642
Emails:
j*****@insightbb.com
May be related to:
- Phone Numbers (1)
- Addresses (4)
- Email Addresses (1)
- Social Profiles (39)
- Relatives (1)
Jacob Stackhouse Summary
1 individuals identified as Jacob Stackhouse were located in Pennsylvania. Predominantly, they reside in York, PA. Public records indicate that the ages of these individuals span from 90 to 90 years old. Some possible relatives include Catherine Stackhouse. Additionally, our search revealed a collective total of 4 phone numbers associated with Jacob Stackhouse, one of which is (717) 741-0411. 717 are some of the most popular area codes for these people.Jacob Stackhouse in Numbers
Statistics based on the US Census data for all 1 people with this name.Single vs. Married
- Married100%
- Single0%
Alive vs. Deceased
- Deceased17%
- Alive83%
- <25k
- 25-50k
- 50-75k
- 75-100k
- 100-125k
- 125-150k
- 150-200k
- 200k+
- 34.2%
- 39.6%
- 35.2%
- 26.8%
- 19.8%
- 15.9%
- 20.5%
- 25.9%
The average income for Jacob Stackhouse is 35k
- Gmail
- Yahoo
- Outlook
- AOL
- Other
- 63%
- 11%
- 8%
- 3%
- 15%
- Verizon
- T-Mobile
- AT&T
- Mint Mobile
- Other
- 33%
- 19%
- 42%
- 1%
- 5%
99
Average Age
- 0-1823%
- 18-259%
- 25-3514%
- 35-4513%
- 45-5512%
- 55-6513%
- 65-8515%
- 85+2%
Jacob Stackhouse F.A.Q.
Discover our primary finding for Jacob Stackhouse in under 60 seconds!
How old is Jacob Stackhouse?
Jacob Stackhouse is 90 years old.
What is Jacob Stackhouse's last known address?
2315 Knobhill Rd, York, PA, 17403
What is Jacob Stackhouse's last contact number?
Jacob Stackhouse's phone number is (717) 741-0411.
What is Jacob Stackhouse's email address?
j*****@insightbb.com
Is Jacob Stackhouse married?
100% of people matching the name Jacob Stackhouse are married.
Does Jacob Stackhouse have a criminal record?
No criminal records found matching the name Jacob Stackhouse.